RegEx for matching several occurrences after lookahead

Question

I got following passage in a text file:

(default) AA / BBB)
ASDF / XYZ / GE
(default) CCCC)

I want to match all uppercase letters (2-4) after (default) to the closing bracket, so AA, BBB and CCCC are matched.

This is what i came up with, but it doesn't match the BBB:

(?<=default\)\s)[A-Z]{2,4}

So what am I missing to match more than one group of uppercase letters after (default)?

Answer 1

If we wish to only match the pattern in the question, we would just simply pass our desired cases and fail the other one using (default):

\(default\)(.+?([A-Z]{2,4}).+?([A-Z]{2,4})|.+?([A-Z]{2,4}))

Demo 1

or:

(?=\(default\))(.+?([A-Z]{2,4}).+?([A-Z]{2,4})|.+?([A-Z]{2,4})).+

Demo 2

const regex = /\(default\)(.+?([A-Z]{2,4}).+?([A-Z]{2,4})|.+?([A-Z]{2,4}))/gm;
const str = `(default) AA / BBB)
ASDF / XYZ / GE
(default) CCCC)`;
let m;

while ((m = regex.exec(str)) !== null) {
    // This is necessary to avoid infinite loops with zero-width matches
    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
    
    // The result can be accessed through the `m`-variable.
    m.forEach((match, groupIndex) => {
        console.log(`Found match, group ${groupIndex}: ${match}`);
    });
}

RegEx Circuit

jex.im visualizes regular expressions: