How do I pass a value into a python function without calling?

I was unable to find a reasonable way to create a variable which calls a function requiring parameters.

Here is a simplified version of my code. I would like print_hello to print hello when it is called, and not when it is defined.

print_hello = print('hello')

When I define print_hello, it calls print('hello'). When I call print_hello, it gives me an error. How do I fix this?

Solution

Just define print_hello as a lambda function

>>> print_hello = lambda: print('hello')
>>> print_hello()
hello

To delay execution, you'll have to wrap the call to print in another function. A lambda is less code than defining another function.

Note: that pep08 recommends using a def function rather than a lambda when assigning to a variable. See here. So @Sheldores answer is probably the way to go.