First of all, thanks for all the help thus far.
Complete code can be found here
I have trouble understanding these lines. I wrote some comments...
The line, for example, mov es:[si+6], al means move data in al to the memory address marked by si+6 (I think this would be an offset calculation).
Then what is add si,40 in the loop?
Any helps mean everything to me! Thank you.
L0_95: ; this segment prints ASCII code 0 - 95
mov si,6 ; refers to the string we declared at the beginning
mov cx,4 ; I think this is the height?
C1A:
; this loop adds the name of the column
mov al,string[0]
mov es:[si],al
mov al,string[2]
mov es:[si+6],al
mov al,string[4]
mov es:[si+24],al
mov al,string[6]
mov es:[si+28],al
add si,40 ;;;; what is this line?
loop C1A
mov si,122 ;;;; and these three lines?
mov bx,0
mov cx,4
C1B:push cx
mov cx,24
add si,40
C1C:push cx
call DEC_CONVERT
add si,2
call HEX_CONVERT
add si,2
call BIN_CONVERT
add si,2
call CHAR_CONVERT
inc bx
add si,126
pop cx
loop C1C
pop cx
sub si,3840
loop C1B
ret
L96_191:
add si advances the si register by 40.
mov si,122 sets the si register to 122, probably the address of some data. The remaining two instructions should now be self-explanatory.