NFA to DFA conversion confusion?

Question

I have this NFA in the book given:

And their solved DFA result was this:

But According to my solved solution (by finding e-closure of each state), it looks something like this:

    |  a   |  b  | c
----+----- +-----+---
ABD | CEBD |  Φ  | C
BD  | EBD  |  Φ  | C
C   |  Φ   | EBD | Φ
D   | EBD  |  Φ  | Φ
EBD | EBD  |  Φ  | C
CEBD| EBD  | EBD | C

What am I missing?

Answer 1

Your solution is identical to the DFA diagram, with two differences:

• Your table contains unreachable states (BD, D). Those are culled from the diagram.
• There is a misprint in the diagram. The two arrows between {C} and {BDE} have their labels switched. (The arrow going from {C} to {BDE} should be labeled b, and the arrow from {BDE} to {C} should be labeled c.)