My example only returns BMW 2010
.
How do I get it to return AUDI 2000
and BMW 2010
?
declare
sample_json varchar2 (32767)
:= '
[{"NAME":"AUDI","YEAR":"2000"},{"NAME":"BMW","YEAR":"2010"}]
';
begin
apex_json.parse (sample_json);
dbms_output.put_line (apex_json.get_varchar2 ('NAME'));
dbms_output.put_line (apex_json.get_varchar2 ('YEAR'));
end;
TL;DR - You cannot as you have duplicate keys in an object.
- Objects
An object structure is represented as a pair of curly brackets surrounding zero or more name/value pairs (or members). A name is a string. A single colon comes after each name, separating the name from the value. A single comma separates a value from a following name. The names within an object SHOULD be unique.
(Added emphasis)
{"NAME":"AUDI","YEAR":"2000","NAME":"BMW","YEAR":"2010"}
While technically it is syntactically correct JSON, it does not make sense as you are duplicating keys so most (every) JSON parsers following RFC 7159 will overwrite the first instance of a key with later occurrences so your JSON is effectively:
{"NAME":"BMW","YEAR":"2010"}
And you cannot get AUDI
/2000
from the output (unless you parse the JSON by hand).
If you want to send multiple values then you should use an array:
[{"NAME":"AUDI","YEAR":"2000"},{"NAME":"BMW","YEAR":"2010"}]
Update
You can try:
declare
sample_json varchar2(32767) := '{"data":[{"NAME":"AUDI","YEAR":"2000"},{"NAME":"BMW","YEAR":"2010"}]}';
begin
apex_json.parse (sample_json);
dbms_output.put_line (apex_json.get_varchar2 ('data[1].NAME'));
dbms_output.put_line (apex_json.get_varchar2 ('data[1].YEAR'));
dbms_output.put_line (apex_json.get_varchar2 ('data[2].NAME'));
dbms_output.put_line (apex_json.get_varchar2 ('data[2].YEAR'));
end;
or (if apex will accept an array as its outer object):
declare
sample_json varchar2(32767) := '[{"NAME":"AUDI","YEAR":"2000"},{"NAME":"BMW","YEAR":"2010"}]';
begin
apex_json.parse (sample_json);
FOR i IN 1 .. 2 LOOP
dbms_output.put_line (apex_json.get_varchar2(p_path=>'[%d].NAME',p0=>i));
dbms_output.put_line (apex_json.get_varchar2(p_path=>'[%d].YEAR',p0=>i));
END LOOP;
end;