python3 default class attribute to method in same class

Question

class Test:
    func = self.func2 # default: func is func2 by default
    # tried Test.func2 as well and Pycharm shows error

    def __init__(self, func=None):
        if func is not None:
            self.func = func

    def func1(self):
        pass

    def func2(self):
        pass

Can anyone advise how to achieve something like the above?

I have tried setting the func parameter to default to func2 in the constructor too but this also errors.

so later, somewhere in the class Test, I can just call self.func instead of repeatedly running conditions to find out whether func1 or func2 should be used

self.func()

**** SOLUTION (what I did) ****

in the main.py:

t = Test(func=Test.func1)
t.func(t, **kwargs)

this should successfully call t.func1 (or t.func2 if specified) with access to the t instance_attributes through a call of higher order method t.func

Answer 1

You could set the default in the __init__ method, based on the value of the func parameter:

Maybe something like this:

class Test:

    def __init__(self, func=None):
        if func is None:
            self.func = self.func2
        else:
            self.func = func

    def func1():
        print('func1')

    def func2(self):
        print('func2')

Test().func()
Test(Test.func1).func()

output:

func2
func1