Is there any way to repeat a Func<T, T> with Enumerable.Repeat method in C#?

I wrote a function that accepts (Func & int N) and repeats the Func N times and returns a result.

public IEnumerable<T> MyFunction(Func<T, T> function, int iteration)
{

}

Is there any way to repeat a function using Enumerable.Repeat?

public IEnumerable<T> MyFunction(Func<T, T> function, int iteration)
{
    yield return Enumerable.Repeat<T>(function.Invoke(), iteration);
}

I tried to run the code above, but the function runs once.

Solution

There is a way, although I'm not sure what it proves.

static public IEnumerable<T> MyFunction<T>(Func<T> function, int iteration)
{
    return Enumerable.Repeat(function, iteration).Select( x => x() );
}

public static void Main()
{
    int n = 0;

    foreach (var i in MyFunction(() => n++, 10)) Console.WriteLine(i);
}

For some reason though it is more common to see people do it this way:

    return Enumerable.Range(0, iteration).Select( x => function() );

I see the latter construct on Stackoverflow all the time.

Output: