I am trying to integrate the following function using a Monte Carlo Integration. The interval I want to integrate is x <- seq(0, 1, by = 0.01)
and y <- seq(0, 1, by = 0.01)
.
my.f <- function(x, y){
result = x^2 + sin(x) + exp(cos(y))
return(result)
}
I calculated the integral using the cubature
package.
library(cubature)
library(plotly)
# Rewriting the function, so it can be integrated
cub.function <- function(x){
result = x[1]^2 + sin(x[1]) + exp(cos(x[2]))
return(result)
}
cub.integral <- adaptIntegrate(f = cub.function, lowerLimit = c(0,0), upperLimit = c(1,1))
The result is 3.134606. But when I use my Monte Carlo Integration Code, see below, my result is about 1.396652. My code is wrong by more than a factor of 2!
What I did:
Since I need a volume to conduct a Monte Carlo Integration, I calculated the function values on the mentioned interval. This will give me an estimation of the maximum and minimum of the function.
# My data range
x <- seq(0, 1, by = 0.01)
y <- seq(0, 1, by = 0.01)
# The matrix, where I save the results
my.f.values <- matrix(0, nrow = length(x), ncol = length(y))
# Calculation of the function values
for(i in 1:length(x)){
for(j in 1:length(y)){
my.f.values[i,j] <- my.f(x = x[i], y = y[j])
}
}
# The maximum and minimum of the function values
max(my.f.values)
min(my.f.values)
# Plotting the surface, but this is not necessary
plot_ly(y = x, x = y, z = my.f.values) %>% add_surface()
So, the volume that we need is simply the maximum of the function values, since 1 * 1 * 4.559753
is simply 4.559753
.
# Now, the Monte Carlo Integration
# I found the code online and modified it a bit.
monte = function(x){
tests = rep(0,x)
hits = 0
for(i in 1:x){
y = c(runif(2, min = 0, max = 1), # y[1] is y; y[2] is y
runif(1, min = 0, max = max(my.f.values))) # y[3] is z
if(y[3] < y[1]**2+sin(y[1])*exp(cos(y[2]))){
hits = hits + 1
}
prop = hits / i
est = prop * max(my.f.values)
tests[i] = est
}
return(tests)
}
size = 10000
res = monte(size)
plot(res, type = "l")
lines(x = 1:size, y = rep(cub.integral$integral, size), col = "red")
So, the result is completely wrong. But if I change the function a bit, suddenly is works.
monte = function(x){
tests = rep(0,x)
hits = 0
for(i in 1:x){
x = runif(1)
y = runif(1)
z = runif(1, min = 0, max = max(my.f.values))
if(z < my.f(x = x, y = y)){
hits = hits + 1
}
prop = hits / i
est = prop * max(my.f.values)
tests[i] = est
}
return(tests)
}
size = 10000
res = monte(size)
plot(res, type = "l")
lines(x = 1:size, y = rep(cub.integral$integral, size), col = "red")
Can somebody explain why the result suddenly changes? To me, both functions seem to do the exact same thing.
In your (first) code for monte
, this line is in error:
y[3] < y[1]**2+sin(y[1])*exp(cos(y[2]))
Given your definition of my.f
, it should surely be
y[3] < y[1]**2 + sin(y[1]) + exp(cos(y[2]))
Or..., given that you shouldn't be repeating yourself unnecessarily:
y[3] < my.f(y[1], y[2])