Introduction
I'm trying to get the difference in seconds from two Epochs
i.e
2019-05-22 18:28:56 -> 1558542536 seconds
2019-07-22 19:00:00 -> 1563814800 seconds
The diff will be: 5,272,264 seconds
This date format comes from a binary file as a String
My code
public static void main(String[] args) throws ParseException
{
String regEpoch = "";
long result = 0;
//System.out.println((fecha = dateFormat.format(date)));
try(RandomAccessFile raf = new RandomAccessFile("binario2.txt", "rw")){
//user inputs a code (for now, doesn't matter if exists or not)
System.out.print("Input a code to look for: ");
String code = scan.next();
while(!code.matches("\\d+"))
{
System.out.println("[ERROR] Only digits accepted");
System.out.print("Input a code to look for: ");
code = scan.next();
}
//Gets the current date in seconds
long getSecs = (new Date().getTime())/1000;
System.out.println("Current tiem in secs: " + getSecs);
//We are "randomly accessing" a binary file. The is no problem here at all. It just works.
//Sets the pointer where I want it, again... this works fine.
raf.seek(27+(80*Integer.parseInt(code)));
//Read the String date correctly, which is 2019-05-22 18:28:56
System.out.println(raf.readUTF());
/*
//Attempt 2
System.out.println(java.time.Instant.ofEpochSecond(Long.parseLong(raf.readUTF())));
Long millis = new SimpleDateFormat("yyyy/MM/ss hh:mm:ss").parse(raf.readUTF()).getTime();
System.out.println(millis);
*/
//Let's try to convert it into seconds... No we can't due to -> Unparseable date: "2019-05-22 18:28:56"
Date dt = dateFormat.parse(raf.readUTF());
long epoch = dt.getTime();
System.out.println("Result is: " + (int)(epoch*1000));
}catch(IOException e){System.out.println("[ERROR] " + e);}
}
Problem
I have read many questions in how to turn seconds into Epoch, but what about the reverse?
So far what I tried only gets the seconds from the Date with SimpleDateFormat but those are not what I expected...
What do I expect from this
I am currently doing homework and I have been task with calculating the price for a parking ticket and I thought, what if the car doesn't leave, let's say... in a week?
If I work only in the format of hh:mm:ss
those cars who stay there a whole week will only pay for one day.
ChronoUnit
I always use ChronoUnit
for calculations like this. Works fine.
package test;
import java.text.ParseException;
import java.time.LocalDateTime;
import java.time.temporal.ChronoUnit;
public class Test2 {
public static void main(String[] args) throws ParseException {
LocalDateTime date1 = LocalDateTime.parse("2019-05-22T18:58:56");
LocalDateTime date2 = LocalDateTime.parse("2019-05-23T19:00:00"); //LocalDateTime.now();
long seconds = ChronoUnit.SECONDS.between(date1, date2);
System.out.println(seconds);
}
}
Output
86464
For converting to date with SimpleDateFormat, you can see e.g. Java time since the epoch