Call method of base class from derived class object python

Question

I have two class and methods having same name .I have the object of derived class. When i call the method (foo) from derived class object it should call the base class method.

class A:
    def foo(self):
        print "A Foo"

class B(A):
    def foo(self):
        print "B Foo"

b = B()
b.foo() # "B Foo"

After doing some search i got some solution as below and not sure whether it is proper way of doing it or not

a = A()
b.__class__.__bases__[0].foo(a) # A Foo

Is there any better way of doing it.

Answer 1

If you're using Python 3, use super:

class A:
    def talk(self):
        print('Hi from A-land!')

class B(A):
    def talk(self):
        print('Hello from B-land!')

    def pass_message(self):
        super().talk()

b = B()
b.talk()
b.pass_message()

Output:

Hello from B-land!
Hi from A-land!

You can do the same thing in Python 2 if you inherit from object and specify the parameters of super:

class B(A):
    def talk(self):
        print('Hello from B-land!')

    def pass_message(self):
        super(B, self).talk()

b = B()
b.talk()
b.pass_message()

Output:

Hello from B-land!
Hi from A-land!

You can also call the method as if it were a free function:

A.talk(b)
B.talk(b)  # the same as b.talk()

Output:

Hi from A-land!
Hello from B-land!