I want to make JavaFX spinner with 3 decimal places as a double value, so I just made Spinner
like this:
Spinner<Double> spinner = new Spinner<Double>();
SpinnerValueFactory<Double> valueFactory =
new SpinnerValueFactory.DoubleSpinnerValueFactory(0, 512, 51.197, 1);
spinner.setValueFactory(valueFactory);
spinner.setEditable(true);
I just made spinner with initial value as 51.197, but when I run this code, initial value is 51.2; and when I edit spinner as 52.666, I can't use this value. I think that the decimal place is problem.
I want to use value form as ###.###
. How can I handle JavaFX Spinner
decimal place?
I solved this problem with StringConverter
.
StringConverter<Double> doubleConverter = new StringConverter<Double>() {
private final DecimalFormat df = new DecimalFormat("###.###");
@Override
public String toString(Double object) {
if (object == null) {return "";}
return df.format(object);}
@Override
public Double fromString(String string) {
try {
if (string == null) {return null;}
string = string.trim();
if (string.length() < 1) {return null;}
return df.parse(string).doubleValue();
} catch (ParseException ex) {throw new RuntimeException(ex);}
}
};
Spinner<Double> spinner = new Spinner<Double>();
SpinnerValueFactory<Double> valueFactory = new SpinnerValueFactory.DoubleSpinnerValueFactory(0, 512, 51.197, 1);
spinner.setValueFactory(valueFactory);
spinner.setEditable(true);
SpinnerValueFactory.setConverter(doubleConverter);