RegEx for ignoring parentheses in a string

Question

These is a string like this:

strs = "Tierd-Branden This is (L.A.) 105  / New (Even L.A.A)"

After trying the following code, I don't get my expected output.

and this is my code:

import re, itertools
strs = "Tierd-Branden This is (U.C.) 105  / New (Even L.A.A)"
print re.findall(r"[\w']+[\w\.]", strs)

I expect This:

['Tierd', 'Branden', 'This', 'is', 'L.A.', '105', 'New', 'Even', 'L.A.A']

But, I get this:

['Tierd', 'Branden', 'This', 'is', 'L.', 'A.', '105', 'New', 'Even', 'L.', 'A.']

My question is how to keep content of parenthesis with . linked as a list element?

Answer 1

The [\w']+[\w\.] pattern matches 1 or more word or ' chars and then a word or . char. Hence, it cannot match chunks of word or ' chars that have more than 1 dot in them.

I suggest using

r"\w[\w'.]*"

See the regex demo and a Regulex graph:

Details

• \w - a word char
• [\w'.]* - 0 or more word, ' and . chars.