Sequential execution of IO from Future

Question

I have simple combinations of two IO with sending message to Telegram bot

def send:Future[Message] = request(SendMessage(chatID, msg))

How to combine IO in greeting to get output "second" after "first" every time. I tried to use *>, flatMap, IO.fromFuture but the result was different.

first
second

second 
first

  def greeting(chatId: Long): IO[Unit] =
    IO(request(SendMessage(chatId, "first"))) *>
    IO(request(SendMessage(chatId, "second")))

  override def onMessage(message: Message) = message.text match {
    case Some(_) => greeting(message.chat.id)
      .unsafeRunAsyncAndForget()
  }

Answer 1

The following snippet works, it does not start the second IO / Future until the first one completes.

import scala.concurrent.Future
import scala.concurrent.ExecutionContext.Implicits.global
import cats.effect.IO

def send(message: => String): Future[Unit] =
  Future {
    Thread.sleep(2000);
    println(message)
  }

def greeting: IO[Unit] =
  for {
   _ <- IO.fromFuture(IO(send("First")))
   _ <- IO.fromFuture(IO(send("Second")))
  } yield ()

greeting.unsafeRunAsyncAndForget()