Execute return as function caller

Question

Is there a way to execute a return statement as a function's caller? Take:

index.php:

require action.php

action.php:

require check.php
checkAccess() || return;
doSomeSecretStuff();

check.php:

function checkAccess() {
    if(loggedIn)
        return true;
    return false;
}

and I was wondering if there is a way to execute that return statement forcing action.php to stop from inside checkAccess()?

kinda like get_function_caller().eval("return");

(super-pseudo code)

Answer 1

If you have this:

check();
foo();

There is no way that check could return for you, so it's guaranteed that foo will be executed. And that's a good thing, otherwise you'd have no guarantees about your execution flow in your code.

The only way this may skip the execution of foo is if a fatal error occurred in check and everything halts, or—and here it comes—if check throws an exception.

You'd use this something like this:

let foo = false;

function assertFoo() {
  if (!foo) {
    throw new Error('Not enough foo');
  }
}

function bar() {
  assertFoo();
  console.log('Barrr!');
}

try {
  bar();
} catch (e) {
  console.log(e.message);
}