I'm using openpyxl
library to do some excel cut/paste operations on spreadsheets.
Let's say that my operations produce the following data (please use it for reproducibility purposes):
col1;col2
1;0,17153686
2;0,615324797
3;0,573701744
4;0,503462355
5;0,154284926
6;0,10027259
7;0,926526263
8;0,871108863
9;0,048035143
10;0,38731583
11;0,48529708
12;0,901046699
13;0,985505734
14;0,606868435
15;0,280662943
16;0,356188065
17;0,102727139
18;0,800757985
19;0,767509347
20;0,418477445
21;0,751892035
22;0,959923786
23;0,524754643
24;0,014140778
25;0,267427799
26;0,666726192
27;0,019314009
28;0,764133187
29;0,587031993
This is the code that chooses the active cell according to an argument given:
from openpyxl import load_workbook, Workbook
def set_active_cell(new_file_name, active_row):
print(active_row)
workbook = load_workbook(new_file_name)
sheet = workbook.get_sheet_names()[0] #get the name of first sheet
worksheet = workbook.get_sheet_by_name(sheet)
coords = "A" + str(active_row)
print(coords)
# worksheet.cell(row=active_row, column=1)
worksheet.sheet_view.selection[0].activeCell = coords
worksheet.sheet_view.selection[0].sqref = coords
workbook.save(new_file_name)
if __name__ == "__main__":
set_active_cell("data.xlsx", 28)
As you can see on the attached image my default view encompasses the first 18 rows. If active_row
is smaller or equal to 18 I get what I want: I can see the active cell in my starting view of the Excel file.
However, any active_row
's value greater than 18 results in the problem. The active cell is chosen correctly, but my starting view is still the first 18 rows and I need to scroll down in order the reach the active cell.
Is there any way to change the view with using openpyxl
?
Scrolling is done by adjusting the openpyxl.worksheet.views.SheetView.topLeftCell variable.
You can scroll to your coords
variable with:
worksheet.sheet_view.topLeftCell = coords
You can find more details in the openpyxl documentation.