When i try to input e.g. "help move" this code prints the corresponding help message to "move" and the default value. But if I understand dict.get(key[, value]) right, the default value should only come up if the key (e.g. "run" instead of "move") is not in the dictionary.
I've tried to check if my key is a string and has no whitespace. Don't know what / how to check else.
#!/usr/bin/env python3
def show_help(*args):
if not args:
print('This is a simple help text.')
else:
a = args[0][0]
str_move = 'This is special help text.'
help_cmd = {"movement" : str_move, "move" : str_move,
"go" : str_move}
#print(a) # print out the exact string
#print(type(a)) # to make sure "a" is a string (<class 'str'>)
print(help_cmd.get(a), 'Sorry, I cannot help you.')
commands = {"help" : show_help, "h" : show_help}
cmd = input("> ").lower().split(" ") # here comes a small parser for user input
try:
if len(cmd) > 1:
commands[cmd[0]](cmd[1:])
else:
commands[cmd[0]]()
except KeyError:
print("Command unkown.")
I excpect the ouput This is a special help text.
if I enter help move
, but the actual output is This is special help text. Sorry, I cannot help you with "move".
.
The crux of the issue is in this line:
print(help_cmd.get(a), 'Sorry, I cannot help you with "{}".'.format(a))
Your default is outside of the call to get, so it is not acting as a default and is being concatenated. For it to be a default, revise to:
print(help_cmd.get(a, 'Sorry, I cannot help you with "{}".'.format(a)))