My codes runs well, but have one flaw. They are not saving accordingly. For example, Let's say I caught 3 jpeg files, when I ran the codes, it saves 3 times on slot 1, 3 times on slot 2, and 3 times on slot 3. So I ended up with 3 same files.
I think there is something wrong with my looping logic?
If I changed for n in range(len(soup_imgs)):
to for n in range(len(src)):
, the operation saves infinitely of the last jpeg files.
soup_imgs = soup.find(name='div', attrs={'class':'t_msgfont'}).find_all('img', alt="", src=re.compile(".jpg"))
for i in soup_imgs:
src = i['src']
print(src)
dirPath = "C:\\__SPublication__\\"
img_folder = dirPath + '/' + soup_title + '/'
if (os.path.exists(img_folder)):
pass
else:
os.mkdir(img_folder)
for n in range(len(src)):
n += 1
img_name = dirPath + '/' + soup_title + '/' + str({}).format(n) + '.jpg'
img_files = open(img_name, 'wb')
img_files.write(requests.get(src).content)
print("Outputs:" + img_name)
I am amateur in coding, just started not long ago as a hobby of mine. Please give me some guidance, chiefs.
Try this when you are writing your image files:
from os import path
for i, img in enumerate(soup_imgs):
src = img['src']
img_name = path.join(dirPath, soup_title, "{}.jpg".format(i))
with open(img_name, 'wb') as f:
f.write(requests.get(src).content)
print("Outputs:{}".format(img_name))
You need to loop over all image sources, rather than using the last src
value from a previous for
block.
I've also added a safer method for joining directory and file paths that should be OS independent. Finally, when opening a file, always use the with open() as f:
construct - this way Python will automatically close the filehandle for you.