I found a few pages on moving vector range to another vector, however I am struggling to make it work.
I would like to move elements from sourceVect to destVect, with the elements between sourceVect[1] to sourceVect[1+numToCopy] being moved to the beginning of sourceVect. I tried to do this in the following way:
vector<int> destVect;
vector<int> sourceVect = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20};
int numToCopy = 7;
vector<int>::iterator itSource = sourceVect.begin();
vector<int>::iterator itSourceEnd = sourceVect.begin();
advance(itSource, 1);
advance(itSourceEnd, 1+numToCopy);
std::copy(itSource, itSourceEnd, destVect.begin()); //copy(first,last,output vector ite)
for (vector<int>::iterator it = destVect.begin(); it != destVect.end(); ++it)
cout << ' ' << *it;
But I am getting Debug Assertion Failed, vector iterator + offset out of range in Visual studio. Please note that I am only trying it out in Visual Studio 2015, it has to be implemented in C++98 for mbed at the end, meaning I can't use std::next for example.
std::copy() will not create new elements in the destination container. That means you need to create destVect with the correct size:
vector<int> sourceVect = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20};
vector<int> destVect(sourceVect.size() - 1);
If you can't create it with the correct size, just resize it later on, at the point where you know the size:
destVect.resize(sourceVect.size() - 1);
You can now copy:
copy(sourceVect.begin() + 1, sourceVect.end(), destVect.begin());
However, you can just create destVect with the correct contents to begin with. You don't need to manually copy anything:
vector<int> sourceVect = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20};
vector<int> destVect(sourceVect.begin() + 1, sourceVect.end());
This is the fastest way to do this and (perhaps more importantly) it's not prone to errors. If you do an std::copy but your destination container's size is not large enough, you end up writing into non-allocated memory (buffer overflow.)