Suppose we have a simple one-to-many relationship between Company and Employee, is there a way to query all companies and have a list of employees in the attribute of each company?
class Company(Base):
__tablename__ = 'company'
id = Column(Integer, primary_key=True)
name = Column(String)
class Employee(Base):
__tablename__ = 'employee'
id = Column(Integer, primary_key=True)
first_name = Column(String)
last_name = Column(String)
company_id = Column(Integer, ForeignKey(Company.id))
I'm looking for something like this:
>>> result = db.session.query(Company).join(Employee).all()
>>> result[0].Employee
[<Employee object at 0x...>, <Employee object at 0x...>]
The size of result should be same as the number of rows in company table.
I tried the following and it gives tuple of objects (which makes sense) instead of nice parent / child structure:
>>> db.session.query(Company, Employee).filter(Company.id = Employee.company_id).all()
It's not hard to convert this into my desired object structure but just wanted to see if there's any shortcut.
You could do something like this:
class Company(Base):
__tablename__ = 'company'
id = Column(Integer, primary_key=True)
name = Column(String)
employees = db.session.query(Company, Employee).filter(Company.id = self.id).all()
self.employee_list = ['{0} {1}'.format(c.first_name, c.last_name) for c in employees]
Then you could access a employee name with Company.employee_list[0]