Python SocketServer error upon connection

Question

I am running a Python server using the socketserver module in Python 3.1. Every time I get a connection from the client (which succeeds client side), my server receives an error. Here is my code:

import socket
import socketserver
import string
import struct

class Server(socketserver.BaseRequestHandler):
    def __init__(self):
        self.address = self.client_address[0]
        print("%s connected." % str(self.address[1]))
    def handle(self):
        message = self.request.recv(1024).decode().strip()
        print("%s sent: '%s'" % (self.address,message))

if __name__ == "__main__":
    server = socketserver.TCPServer(("localhost",22085), Server)
    print("Socket created. . .")
    print("Awaiting connections. . .")
    server.serve_forever()

And here is my error:

----------------------------------------
Exception happened during processing of request from ('127.0.0.1', 49669)
----------------------------------------
Traceback (most recent call last):
  File "C:\Python31\lib\socketserver.py", line 281, in _handle_request_noblock
    self.process_request(request, client_address)
  File "C:\Python31\lib\socketserver.py", line 307, in process_request
    self.finish_request(request, client_address)
  File "C:\Python31\lib\socketserver.py", line 320, in finish_request
    self.RequestHandlerClass(request, client_address, self)
TypeError: __init__() takes exactly 1 positional argument (4 given)

The odd thing I noticed about the error is that the port it gives on the second line is different than the port I'm using. I'm not really sure what the error is here...

Thanks for the help.

Answer 1

Try calling the __init__ method of the superclass:

class Server(socketserver.BaseRequestHandler):
    def __init__(self):
        self.address = self.client_address[0]
        print("%s connected." % str(self.address[1]))
        super(Server,self).__init__()                  # Init your base class