How to get a bullet point Black round circle instead of html code using XSLT

Question

I have a simple xslt that transforms an xml to an xsl-fo but when my xml is generated it produces bullet points in

•

when I use my transformation to transform to xsl-fo and pass that to ecrion to render a pdf it does not recognise the html code for bullet point I would like to add some condition to my XSLT to change that to a full black circle bullet point any suggestion please

 <?xml version="1.0"?>
 <xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" omit-xml-declaration="yes" indent="yes" />

<xsl:template match="/doc">
<Generic><xsl:apply-templates /></Generic>
</xsl:template>

<xsl:template match="*|@*">
<xsl:copy>
  <xsl:apply-templates select="@*" />
  <xsl:apply-templates />
</xsl:copy>
</xsl:template>

<xsl:template match="&#149;">
<xsl:copy>
  <xsl:apply-templates select="•" />
  <xsl:apply-templates />
 </xsl:copy>
</xsl:template>
</xsl:transform>

Answer 1

Without seeing your XML input and the expected output, we can only guess. Try perhaps:

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="/doc">
    <Generic>
        <xsl:apply-templates />
    </Generic>
</xsl:template>

<xsl:template match="text()">
    <xsl:value-of select="translate(., '&#149;', '&#8226;')" />
</xsl:template>

</xsl:stylesheet>

This will replace all occurrences of the MESSAGE WAITING control character (•) with the BULLET character (•).