how to check if integer which I want inside my value(if int is not iterable)

Question

I am trying to run this test code:

def test(**kwargs):
    for key, value in kwargs.items():
        if 'sdk' in key:
            print value
            if 1 in value:
                print 'HelloWorld'    

test(sdk=1)

But of course it will give me error since integer is not iterable , so how do you guys check if integer which you want inside value? Thank you

Answer 1

The expression you actually should be using is if value == 1.

if 1 in value expects that value is an iterable (e.g., an array or a dict) and returns True if 1 is contained in value, and False otherwise.

If value is not an iterable, you'll get an exception:

>>> arr = [1, 2, 3]
>>> 1 in arr
True
>>> 4 in arr
False
>>> not_arr = 1
>>> 1 in not_arr
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: argument of type 'int' is not iterable
>>> not_arr == 1
True
>>> not_arr == 2
False