Protected method call in Python?

Question

I have a sequence of calls that I need to make, all of which could throw an exception and I want a good way of protecting the calls. I am trying to find a more professional way to do the following in python:

def protected_call(method):
   result = None
   try:
       result= method()
   except:  pass

   return result
class Test():


  def terminate(): 
     protected_call(self.could_throw_exception)
     protected_call(self.receiver.stop)
     protected_call(self.connection.stop)
     #etc

Is there a better way to do this ? Maybe with an annotation ?

Just to clarify, I dont want to put an annotation on the original method ie:

class Receiver():
  @protected
  def stop():
     print 'I dont want to do this'

class Test():
  @protected
  def could_throw_exception():
     print 'dont want this'
  def stop(): 
     self.could_throw_exception()
     self.receiver.stop()

This is what i want:

class Receiver():
  def stop():
     print 'I want this'

class Test():

  def could_throw_exception():
     print 'like this'

  '''This one cares about crashing'''
  def stop()
     self.could_throw_exception()
     self.receiver.stop()
     self.connection.stop()

  '''This one does not'''
  def terminate(): 
     #i want to define it at the call level.
     @protected
     self.could_throw_exception()
     @protected
     self.receiver.stop()

Answer 1

As nmichaels suggested, this kind of thing is best handled via the with statement.

@contextlib.contextmanager
def suppress_exceptions(*exceptions):
    if not exceptions:
        exceptions = Exception
    try:
        yield
    except exceptions:
        # You would log an error here
        # If you have logging in your application
        pass

with suppress_exceptions():
    1/0

print("Ignored the exception!")

with suppress_exceptions(IOError):
    1/0

# The second one will let the exception through