I have a list
like this:
["Dhoni 35 WC 785623", "Sachin 40 Batsman 4500", "Dravid 45 Batsman 50000", "Kumble 41 Bowler 456431", "Srinath 41 Bowler 65465"]
After applying filter I want like this:
["Dhoni WC", "Sachin Batsman", "Dravid Batsman", "Kumble Bowler", "Srinath Bowler"]
I tried out this way
m = sc.parallelize(["Dhoni 35 WC 785623","Sachin 40 Batsman 4500","Dravid 45 Batsman 50000","Kumble 41 Bowler 456431","Srinath 41 Bowler 65465"])
n = m.map(lambda k:k.split(' '))
o = n.map(lambda s:(s[0])) o.collect()
['Dhoni', 'Sachin', 'Dravid', 'Kumble', 'Srinath']
q = n.map(lambda s:s[2])
q.collect()
['WC', 'Batsman', 'Batsman', 'Bowler', 'Bowler']
Provided, all your list items are of same format, one way to achieve this is with map
.
rdd = sc.parallelize(["Dhoni 35 WC 785623","Sachin 40 Batsman 4500","Dravid 45 Batsman 50000","Kumble 41 Bowler 456431","Srinath 41 Bowler 65465"])
rdd.map(lambda x:(x.split(' ')[0]+' '+x.split(' ')[2])).collect()
Output:
['Dhoni WC', 'Sachin Batsman', 'Dravid Batsman', 'Kumble Bowler', 'Srinath Bowler']