How to use *args and self in Python constructor

Question

I need a Python method to have access to self for instance variables and also be able to take any number of arguments. I basically want a method foo that can be called via

foo(a, b, c)

or

foo()

In the class, I think the constructor would be

def foo(self, *args):

Is this correct? Also, fyi, I am new to Python (if you can't tell).

Answer 1

You just have to add it after the self parameter:

class YourClass:
    def foo(self, *args):
        print(args)
    def bar(self, *args, **kwargs):
        print(args)
        print(kwargs)
    def baz(self, **kwargs):
        print(kwargs)

I have also added a method in which you also add **kwargs, and the case in which you add both *args and **kwargs.

Examples

>>> o = YourClass()
>>> o.foo()
()
>>> o.foo(1)
(1,)
>>> o.foo(1, 2)
(1, 2)