I say unexpected because I am clearly not thinking about Try and None correctly. I got here because I was calling a function to return a value for MyVar, and then testing with Trys to ensure the function did not return None. Something like:
def Myfunct():
return "Some_URL"
MyVar = Myfunct()
try:
MyVar is not None:
pass
I could not get the expected TRY result. So I explicitly stated values and tested again. Testing for None via IF gives the right results, but doing the same with TRY gives unexpected results, which come from the code below:
Type of My_Var is: <class 'str'> with value: Some_URL
IF is None: False
IF is not None: True
TRY is None: True
TRY is not None: True
Both Try is None and Try is not None both return True. How is that possible? What am I missing about checking if a value has been set
My_Var = None
My_Var = "Some_URL"
print ("Type of My_Var is:", type(My_Var), "with value: ", My_Var)
if My_Var is None:
print ("IF is None: True")
else:
print ("IF is None: False")
if My_Var is not None:
print ("IF is not None: True")
else:
print ("IF is not None: False")
try:
My_Var is None
print ("TRY is None: True" )
pass
except Exception as e:
print ("TRY is None: False" )
try:
My_Var is not None
print ("TRY is not None: True" )
pass
except Exception as e:
print ("TRY is not None: False" )
try doesn't care about whether a value is True, False, None, or anything else. try executes a block of code if no errors arise, and defers to except if errors do arise.