I defined a random number and i want to check if it is a palindrome java

Question

import java.util.Random;

public class Loop6 {
    public static void main(String[] args) {

        Random number = new Random();
        int value = number.nextInt(1000);
        System.out.println("random number : " + " " + value);

        int rev = 0;
        int dig;

        while (value > 0) {
            dig = value % 10;
            rev = rev * 10;
            rev = rev + dig;
            value = value / 10;
        }
        System.out.println("rev is : " + "" + rev);
        if(value==rev) {
            System.out.println("Palindrome");

        }

    }
}

Answer 1

You code is almost fine, it's just you're updating the initial random number which is not what you want. To keep changes to the code at minimal, I propose you to add a new variable and compare it to the result of your reverse algorithm.

import java.util.Random;

public class Loop6 {
    public static void main(String[] args) {

        Random number = new Random();
        int randomNumber = number.nextInt(1000);  // introduce the initial variable
        int value = randomNumber;  // introduce the variable that will be updated
        System.out.println("random number : " + " " + value);

        int rev = 0;
        int dig;

        while (value > 0) {
            dig = value % 10;
            rev = rev * 10;
            rev = rev + dig;
            value = value / 10;
        }
        System.out.println("rev is : " + "" + rev);
        if (randomNumber == rev) {  // compare the initial variable and the reverse result
            System.out.println("Palindrome");

        }

    }
}