Type with computed property using 'in' from type

Question

I generate a Type Option from object Options using typeof and keyof.

I define another type - Dropdown which have computed property and use the Option using in.

I get an error:

Property 'options2' is missing in type '{ [Options.option1]: string; }'.

How should I implement it right?

const Options = {
  option1: 'option1' as 'options1',
  option2: 'option1' as 'options2',
  option3: 'option1' as 'options3',
}

type Option = typeof Options[keyof typeof Options];
type Dropdown = { [key in Option]: string };

const obj: Dropdown = {
  [Options.option1]: 'test'
}

playground

Answer 1

Thanks to @TitianCernicova-Dragomir I just needed to set the prop optional (?), like this:

const Options = {
  option1: 'option1' as 'options1',
  option2: 'option1' as 'options2',
  option3: 'option1' as 'options3',
}

type Option = typeof Options[keyof typeof Options];
type Dropdown = { [key in Option]?: string };

const obj: Dropdown = {
  [Options.option1]: 'test'
}

Playground