Hello Everyone here i wanted to change, We need to update the strikethrough to be the same diagonal - 45 degrees centered. Please find the code at below...
.Product__widths__button {
background: #FFFFFF;
border: 1px solid #333333;
color: #333333;
display: block;
font-size: 16px;
line-height: 42px;
height: 42px;
text-align: center;
padding-left: 20px;
padding-right: 20px;
}
.Product__widths__button.disabled {
color: #D1D1D1;
background: linear-gradient(to top left, #fff 38px, #D1D1D1, #fff 40px);
border-color: #D1D1D1;
}
<a id="width_1_1" class="Product__widths__button disabled"><span>W</span> (Wide)</a>
Here wanted to display like below image
Please let me if anything more needs from my side. Thanks!!!
If the height is fixed you can set the background size to be a square with dimension equal to height (42px
in your case) and center it like below:
.Product__widths__button {
background: #FFFFFF;
border: 1px solid #333333;
color: #333333;
display: block;
font-size: 16px;
line-height: 42px;
height: 42px;
text-align: center;
padding-left: 20px;
padding-right: 20px;
}
.Product__widths__button.disabled {
color: #D1D1D1;
background:
linear-gradient(to top left,
/*the center is 42px*cos(45deg) = 29.7px, we remove/add pixel around*/
transparent 28px,#D1D1D1,transparent 31px)
center/42px 100% /*background-position/background-size (100% is your height)*/
no-repeat;
border-color: #D1D1D1;
}
<a id="width_1_1" class="Product__widths__button disabled"><span>W</span> (Wide)</a>
Another idea is to make the gradient a big square in case you don't know the exact height and it will work with dynamic height.
.Product__widths__button {
background: #FFFFFF;
border: 1px solid #333333;
color: #333333;
display: block;
font-size: 16px;
line-height: 42px;
text-align: center;
padding-left: 20px;
padding-right: 20px;
}
.Product__widths__button.disabled {
color: #D1D1D1;
background:
linear-gradient(to top left,
/* the center is 500px*cos(45deg) = 353.5px*/
transparent 351px,#D1D1D1,transparent 355px)
center/500px 500px /*background-position/background-size */
no-repeat;
border-color: #D1D1D1;
}
<a id="width_1_1" class="Product__widths__button disabled"><span>W</span> (Wide)</a>
<a id="width_1_1" class="Product__widths__button disabled"><span>W</span> (Wide)<br>another line</a>
Another way without background-size
and background-position
is to simply set the degree to be -45deg
and you need to find the center using calc()
combined with 50%
.Product__widths__button {
background: #FFFFFF;
border: 1px solid #333333;
color: #333333;
display: block;
font-size: 16px;
line-height: 42px;
text-align: center;
padding-left: 20px;
padding-right: 20px;
}
.Product__widths__button.disabled {
color: #D1D1D1;
background:
linear-gradient(-45deg,transparent calc(50% - 2px),#D1D1D1,transparent calc(50% + 2px));
border-color: #D1D1D1;
}
<a id="width_1_1" class="Product__widths__button disabled"><span>W</span> (Wide)</a>
<a id="width_1_1" class="Product__widths__button disabled"><span>W</span> (Wide)<br>another line</a>
You can also try this using a skewed element as background where you will have better support in case you cannot use calc()
.Product__widths__button {
background: #FFFFFF;
border: 1px solid #333333;
color: #333333;
display: block;
font-size: 16px;
line-height: 42px;
text-align: center;
padding-left: 20px;
padding-right: 20px;
position:relative;
z-index:0;
}
.Product__widths__button.disabled {
color: #D1D1D1;
border-color: #D1D1D1;
}
.Product__widths__button.disabled::before {
content:"";
position:absolute;
z-index:-1;
left:0;
top:0;
bottom:0;
width:calc(50% - 2px); /*we remove half the border-width to have a perfect centring*/
border-right:4px solid #D1D1D1;
transform:skewX(-45deg);
}
<a id="width_1_1" class="Product__widths__button disabled"><span>W</span> (Wide)</a>
<a id="width_1_1" class="Product__widths__button disabled"><span>W</span> (Wide)<br>another line</a>