New to Python here.
I am looking for a simple way of creating a list (Output), which returns the count of the elements of another objective list (MyList) while preserving the indexing(?).
This is what I would like to get:
MyList = ["a", "b", "c", "c", "a", "c"]
Output = [ 2 , 1 , 3 , 3 , 2 , 3 ]
I found solutions to a similar problem. Count the number of occurrences for each element in a list.
In : Counter(MyList)
Out : Counter({'a': 2, 'b': 1, 'c': 3})
This, however, returns a Counter object which doesn't preserve the indexing.
I assume that given the keys in the Counter I could construct my desired output, however I am not sure how to proceed.
Extra info, I have pandas imported in my script and MyList is actually a column in a pandas dataframe.
Instead of listcomp as in another solution you can use the function itemgetter:
from collections import Counter
from operator import itemgetter
lst = ["a", "b", "c", "c", "a", "c"]
c = Counter(lst)
itemgetter(*lst)(c)
# (2, 1, 3, 3, 2, 3)
UPDATE: As @ALollz mentioned in the comments this solution seems to be the fastet one. If OP needs a list instead of a tuple the result must be converted wih list.