What is solution for "The file couldn’t be opened." UserInfo={NSURL=ftp:/xxxx:xxx@2011@ftp.xxx.com:21/}?

Question

I am trying to call FTP server api and want to get file name when api is success. Below code I tried for call api,

let host = "ftp.xxx.com"
        let user = "xxx"
        let password = "xxx@2011"
        let port = "21"

       let url = URL(string: "ftp://"+user+":"+password+"@"+host+":"+port+"/")
        var data: Data? = nil
        do {
            if let anUrl = url {
                data = try Data(contentsOf: anUrl)
                print(data!)
            }
        } catch {
            print("Unexpected error: \(error).")
        }

When run this code I am getting error like

Error Domain=NSCocoaErrorDomain Code=256 "The file couldn’t be opened." UserInfo={NSURL=ftp:/xxxx:xxx@2011@ftp.xxx.com:21/}.

Please give me any solution to solve this.

Answer 1

The problem is the plain @ inside the password. This means ftp://xxxx:xxx@2011@ftp.xxx.com:21/ gets interpreted as connecting to server 2011@ftp.xxx.com with username xxxx and password xxx, which is obviously wrong.

The solution should be to URL-encode the special character @ to %40, i.e. use the URL

ftp://xxx:xxx%402011@ftp.xxx.com:21/