I've been able to find multiple solutions to this problem on other languages but can not seem to get it right in R. Here's what I have so far:
Given an array (-2, 0, 1, 3) find the count of triplets less than the sum variable given.
sum = 2
ar<-c(-2, 0, 1, 3);ar
sumtrip<- function (vec,n,sum) {
ctr=0
for (i in 1:n-2){
for (j in i+1:n-1){
for (k in j+1:n){
if ((vec[i]+vec[j]+vec[k]) < sum){
ctr=ctr+1
}
}
}
}
return(ctr)
}
sumtrip(ar,length(ar),sum)
This results in: Error in vec[i] + vec[j] : non-numeric argument to binary operator
You just have bad punctuation. This should do what you want. Please compare your parentheses with mine.
sum = 2
ar<-c(-2, 0, 1, 3);ar
sumtrip<- function (vec,n,sum) {
ctr=0
for (i in 1:(n-2)){
for (j in (i+1):(n-1)){
for (k in (j+1):n){
if ((vec[i]+vec[j]+vec[k]) < sum){
ctr=ctr+1
}
}
}
}
return(ctr)
}
sumtrip(ar,length(ar),sum)