XSLT: in a <p> element, how to replace a line break (<br/>) with successive <alinea> element?

Question

I am trying to transform a <p> element with <br/> elements within into several <alinea>subtext</alinea>. For instance :

<p>subtext<br/>some more text<br/> some more subtext</p>

From the previous <p> I was hoping to simply replace all <br/> into </alinea><alinea> since the template for <p> opens a <alinea> element already.

<xsl:template match="p">
    <para><alinea><xsl:apply-templates/></alinea></para>
</xsl:template>

<xsl:template match="br">
    </alinea><xsl:apply-templates/><alinea>
</xsl:template>

But it is doesn't validate.

Expected result :

<para>
   <alinea>
     subtext
   </alinea>
   <alinea>
     some more text
   </alinea>
   <alinea>
     some more subtext
   </alinea>
 </para>

Answer 1

This is quite easy to do in XSLT 2.0:

<xsl:template match="p">
    <para>
        <xsl:for-each-group select="node()" group-starting-with="br">
            <alinea>
                <xsl:copy-of select="current-group()[not(self::br)]" />
            </alinea>   
        </xsl:for-each-group>
    </para>
</xsl:template>

---

Demo: https://xsltfiddle.liberty-development.net/6r5Gh2Q