I am looking for an expression that will truncate a float to at most a certain number of digits. I want to preserve a certain number of decimals, without having unnecessary trailing 0s.
So, this almost works as desired:
"{0:3.f"}.format(number)
For input 3.123000001:
"{0:.3f}".format(3.1230000001)
'3.123'
Great. But for input 3:
"{0:.3f}".format(3)
'3.000'
I figured out the answer while I was writing the question. Just add .rstrip('0')
to the expression. So:
"{0:3.f}".format(number).rstrip('0')