I know can change all of the label colors using textprops = dict(color = 'white') inside the plt.pie() command however is it possible to have each label have its own color? I have tried the following:
colorlist = ['w','k','r','g']
textprops = [dict(color = c) for c in colorlist]
which results in the error:
AttributeError: 'list' object has no attribute 'setdefault'
textprops = dict(color = colorlist)
which results in a plot with no labels at all, and finally I tried putting my plt.pie() call into a for loop, but even the simplest version of that didn't work.
sizes = [50,50]
plt.figure(figsize=(15,15))
for i in range(len(sizes)):
s = sizes[i]
plt.pie(s)
plt.axis('equal')
plt.show()
This gives the error:
TypeError: len() of unsized object
I don't know what else to try, I'm out of ideas.
You can loop over the texts labels returned by the pie
and colorize each individually.
import matplotlib.pyplot as plt
labels = ["AAA", "BBB", "CCC", "DDD"]
colorlist = ['crimson','k','r','gold']
sizes = [10,20,20,40]
plt.figure()
wedges, texts = plt.pie(sizes, labels=labels)
for text, color in zip(texts, colorlist):
text.set_color(color)
plt.show()