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djangodjango-modelsdjango-viewsdjango-permissions

Formatting a permissions QuerySet so that it just displays the name column


I am trying to list the permissions specific to a model through a query. The goal is to just display the "name" part of the QuerySet. I'm only able to get the output below through the tag: {{ permissions }}

<QuerySet [<Permission: cms | Account meta | Can add Account meta>, <Permission: cms | Account meta | Can change Account meta>, <Permission: cms | Account meta | Can delete Account meta>, <Permission: cms | Account meta | Allows the user to log in as others>, <Permission: cms | Account meta | Allows a user to deactivate/delete other users>, <Permission: cms | Account meta | Allows a user to edit site and role details>, <Permission: cms | Account meta | Can export user details>, <Permission: cms | Account meta | Can view Account meta>]>

models.py

class Account(models.Model):
    user = models.OneToOneField(User, on_delete=models.CASCADE)
    site = models.CharField(max_length=50, choices=(('all', 'all'), ('danielk', 'danielk'), ('flis', 'flis'), ('vmusic', 'vmusic')), blank=True)
    site_role = models.CharField(max_length=50, choices=(('Administrator', 'Administrator'), ('Moderator', 'Moderator'), ('Editor', 'Editor')))
    phone_number = models.CharField(max_length=8)
    birth_date = models.DateField()
    street_adress = models.CharField(max_length=255)
    note = models.TextField(blank=True);
    zip_code = models.CharField(max_length=4)
    city = models.CharField(max_length=255)

    def formatedPhone(self, country=None):
        return phonenumbers.parse(Account.phone_number, "NO")

    """
    def __str__(self):
        return "%s %s" % (self.User.first_name, self.user.last_name)
    """

    def get_absolute_url(self):
        return reverse('account-detail', kwargs={'pk': self.pk})

    class Meta:
        verbose_name = 'Account meta'
        verbose_name_plural = 'Accounts meta'
        permissions = (
            ("has_user_hijack_permission", "Allows the user to log in as others"),
            ("has_user_management", "Allows a user to deactivate/delete other users"),
            ("has_user_site_edit", "Allows a user to edit site and role details"),
            ("has_user_takeout", "Can export user details"),
        )

views.py

class cms_users_user_permissions(generic.DetailView):
    model = Account
    template_name = 'cms/users/cms-users-user-permissions.html'

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context["permissions"] = Permission.objects.filter(content_type=ContentType.objects.get_for_model(Account))
        #context['permissions'] = Permission.objects.filter(content_type_id=7)
        return context

Solution

  • Instead of writing {{ permissions }}, you iterate over the queryset, and each time print the name of the permission, like:

    {% for permission in permissions %}
        {{ permission.name }}
    {% endfor %}