Since I'm new to Java, I have created a method to unzip password protected zip files, I have used zip4j library for unzipping the zip file,the code works fine when the password is correct, but when the password is wrong how to handle the ZipException(net.lingala.zip4j.exception.ZipException: net.lingala.zip4j.exception.ZipException: net.lingala.zip4j.exception.ZipException: Wrong Password for file: Demo.zip)and display appropriate message(Wrong Password!).Please Help, Here is my code.
import net.lingala.zip4j.core.ZipFile;
import net.lingala.zip4j.exception.ZipException;
import net.lingala.zip4j.model.ZipParameters;
import net.lingala.zip4j.util.Zip4jConstants;
public class UnunzipDemo{
public void unzipFilesWithPassword(String sourceZipFilePath,String extractedZipFilePath,String password){
try {
ZipFile zipFile = new ZipFile(sourceZipFilePath);
if (zipFile.isEncrypted()) {
zipFile.setPassword(password);
}
zipFile.extractAll(extractedZipFilePath);
System.out.println("Done");
}
catch (ZipException e) {
e.printStackTrace();
}
}
public static void main(String[] args) {
String sourceZipFilePath="E:/MyFiles/Files/Zip/Demo.zip";
String extractedZipFilePath="E:/MyFiles/Files/Unzip/";
String password="JOEL"; //Correct Password
UnunzipDemo unzipDemo=new UnunzipDemo();
unzipDemo.unzipFilesWithPassword(sourceZipFilePath,extractedZipFilePath,password);
}
}
Maybe you can read the password from console. For instance:
private static String password = "123";
public static void main(String[] args) {
// read the input password from console
// if you have UI, maybe you can read it from some way.
Scanner sc = new Scanner(System.in);
String inputPassword = sc.next();
while (true) {
//do something...
try {
unzip(inputPassword);
break;
} catch (Exception e) {
inputPassword = sc.next();
}
}
}
private static void unzip(String inputPassword) {
if (inputPassword.equals(password)) {
//unzip
} else {
// just demo. In your case, this is ZipException
throw new IllegalArgumentException("wrong password");
}
}