Get URL from HTTP Request node

Question

My msgflow looks like:

MQinput -> Compute node -> HTTP Request

I have override.properties for DEV set to:

MsgflowName#HTTP Request.URLSpecifier = https://myDevUrl.com/id

and another 2 override.properties files for TEST and PROD:

MsgflowName#HTTP Request.URLSpecifier = https://myTestUrl.com/id

and

MsgflowName#HTTP Request.URLSpecifier = https://myProdUrl.com/id

but I want to pass URLs dynamicaly like https://myDevUrl.com/id/123, where 123 is id, which I get in request.

I know that I can use:

SET OutputLocalEnvironment.Destination.HTTP.RequestURL = https://myUrl.com/id/123

but for this command I don't know if that URL is for DEV, TEST or PROD.

I can resolve this by inserting URL for DEV/TEST/PROD to DB, but I'm looking for simpler way.

So my question is:

I there any way to get a URL from HTTP Request node (which is set in override.properties)

Something like:

SET URL = OutputLocalEnvironment.Destination.HTTP.RequestURL;  -- was not worked 

or

is there any other workaround?

Answer 1

Looking at the properties that are accessible from ESQL, you have to go for the workaround.

Define a User-Defined Property (UDP) in the overrides like this:

MsgflowName#TheURL = https://myDevUrl.com/id

Access the UDP like this:

CREATE COMPUTE MODULE YourModule
  DECLARE TheURL EXTERNAL CHARACTER '';

  CREATE FUNCTION Main() RETURNS BOOLEAN
  BEGIN
    DECLARE idFromRequest CHARACTER ...;
    DECLARE url CHARACTER TheURL || '/' || idFromRequest;
    SET OutputLocalEnvironment.Destination.HTTP.RequestURL = url;
    ...