I'm looking for a replacement of
import os
package_dir = os.path.dirname(os.path.abspath(__file__))
file_path = os.path.join(package_dir,'foo.csv')
My working path isn’t the path of the file. So when I want to load a file, I need a way to generate the relative path compared to my working directory.
I want to update to pathlib (or whatever else is out there). But what is the nicest way to do the same?
I found https://stackoverflow.com/a/44188489, but I don't think this solution looks better than my current way.
It's not a duplicate of How to properly determine current script directory?, since I explicitly asked about the nicest way. Most of the solutions in the other post don't look nice, or are already mentioned in the my question. The solution
Path(__file__).with_name("foo.csv")
given here is much better than the solutions given in the other question, since it's easy to understand, and a really pythonic way to solve it. If this question was a dublicate, on the other post an equally good answer would exist.
If you're looking to do the same with pathlib, it could look like this:
from pathlib import Path
package_dir = Path(__file__).parent.absolute()
file_path = package_dir.joinpath("foo.csv")
Unless you're changing current working directory, you may not really need/want to use .absolute().
If you actually do not need to know what package_dir would be, you can also just get the file_path directly:
file_path = Path(__file__).with_name("foo.csv").absolute()
Which gives you new Path replacing the file name.