I want to convert HiveQL query with window function into Scala Spark query... but I'm constantly receiving the same exception.
Problem context: mytable
consists of category
and product
fields. I want to get list with top N frequent product for each category. DF
below is a HiveContext
object
Original query (works correctly):
SELECT category, product, freq FROM (
SELECT category, product, COUNT(*) AS freq,
ROW_NUMBER() OVER (PARTITION BY category ORDER BY COUNT(*) DESC) as seqnum
FROM mytable GROUP BY category, product) ci
WHERE seqnum <= 10;
What I have now (partially converted, doesn't work):
val w = row_number().over(Window.partitionBy("category").orderBy(count("*").desc))
val result = df.select("category", "product").groupBy("category", "product").agg(count("*").as("freq"))
val new_res = result.withColumn("seqNum", w).where(col("seqNum") <= 10).drop("seqNum")
Constantly receiving the following exception:
Exception in thread "main" org.apache.spark.sql.AnalysisException: expression 'category' is neither present in the group by, nor is it an aggregate function. Add to group by or wrap in first() (or first_value) if you don't care which value you get.;
What can be wrong here?
Your mistake is to use aggregate in the orderBy
clause:
.orderBy(count("*").desc)
If written like that, expression introduces new aggregate expression. Instead you should reference existing aggregate by name:
.orderBy("freq")
So your code should look like:
val w = row_number().over(
Window.partitionBy("category").orderBy("freq"))
val result = df.select("category", "product")
.groupBy("category", "product")
.agg(count("*").as("freq"))
val new_res = result
.withColumn("seqNum", w).where(col("seqNum") <= 10)
.drop("seqNum")