3 and 1 being interpreted as strings

Question

I am making a dice rolling program where you try to have a dice roll higher than the computer, although it is completely randomized. I have the function:

def wait(loop, time):
    sleep(time)
    for number in range(loop):
        print('.')
        sleep(time)

That is inteded to cause a ... appear for waiting.

Sample input:

wait(3, 1)

Intended output:

.
.
.

Where it loops 3 times, and waits 1 second between each loop. I am getting the error

TypeError: 'str' object is not callable

I don't understand because it is a number not a string.

I have tried using int() on every part and only some parts For example:

def wait(loop, time):
    sleep(int(time))
    for number in range(int(loop)):
        print('.')
        sleep(int(time))

wait(int(3), int(1))

and

def wait(loop, time):
    sleep(int(time))
    for number in range(int(loop)):
        print('.')
        sleep(int(time))

wait(3, 1)

and

def wait(loop, time):
    sleep(time)
    for number in range(loop):
        print('.')
        sleep(time)

wait(int(3), int(1))

Answer 1

Because you assign a string value to wait this creates a local variable which over-rides the function with a name of wait

 wait = input('\nPress enter to begin the game:')

You can't then call wait(3,1) later because '\nPress enter to begin the game:'(3,1) doesn't make sense.