EDIT
Using VSCode, I had an issue while debugging in a virtual environment that have different packages which are not installed in the base
environment. After activating the environment with the command activate my_env
, I can use the packages in the environment with usual python command as python main.py
. But while debugging, I can't use the packages which are only installed in my_env
. How can I debug a python code in a virtual environment using VSCode?
This is this the summary of the question. The rest has some specific info about my case.
BEFORE EDIT
I am trying to use xmltodict
package with a simple code using visual studio code.
import xmltodict
with open('C:\\Users\\user\\foo.xml') as f:
db_dict = xmltodict.parse(f.read())
print(db_dict)
I have a virtual environment named my_env
, and I installed xmltodict
package in it. When I activate the environment with activate my_env
, this code works fine. But, when I try to use vscode debug option, it gives No module named 'xmltodict'
error. Becuase vscode debug button opens new cmd and run the debugging command in it, I stopped debugging and typed activate my_env
in that cmd and tried to debug again, but still it can't find the module. Also, I tried jupiter notebook in vscode, it also doesn't see the package.
I see that import xmltodict
is underlined with red in vscode and it says Unable to import 'xmltodict'
, but it works when I run it normally from cmd. This happens sometimes for other modules and I don't know why. I installed xmltodict
module using pip
, maybe it causes that.
I am using Visual Studio Code 1.30.1 with Anaconda Python 3.7.1 on Windows 10.
How can I debug a python code in a virtual environment using VSCode? I saw this question, but I don't think it is exactly what I want?
Make sure the environment you want to use is selected in the Python extension for VS Code by running the Select Interpreter
command or via the status bar. Otherwise you can explicitly set the Python interpreter to be used when debugging via the python
setting for your debug config.