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bashshelltrimtr

Shell: Robust way to remove trailing decimal point and zero in case there is a zero

In a bash script I have a (two digit) number with decimal point and one digit following.

In case there's a zero after the decimal separator, I want to trim the separator and the zero.

For

foo=26.5

..there should be no trimming. But in this case: 

foo=26.0

My desired output would be:

foo=26

Is tr the right choice for it?

I tried it with the --delete .0 option but it simply deletes all of both character's appearences.

Thank you!

Solution

  • Not only for bash:

    foo=$(echo "$foo" | sed 's/\.0$//')