I'm trying to do a curl command with python requests. As far as I can tell I'm doing everything correctly but the website won't recognize the api key no matter how I try to include it. Basically, the site I'm trying to reach wants the api key put in the beginning of the url. When I do this with curl, it works perfectly. When I try it via python requests, however, it doesn't work. It also doesn't work to send it in as a key-value pairing in dictionary.
This works
curl -H "Content-Type:application/json" -d '{"ndbno":["11124"],"type":"f"}' [API KEY]@api.nal.usda.gov/ndb/V2/reports
and here's the requests code:
import requests
headers = {'Content-Type': 'application/json',}
data = '{"ndbno":["11124"],"type":"f"}'
response = requests.post('http://[API KEY]@api.nal.usda.gov/ndb/V2/reports', headers=headers, data=data)
The result from this is a json response containing the message: "{'error': {'code': 'API_KEY_MISSING', 'message': 'No api_key was supplied. Get one at http://api.nal.usda.gov:80'}} "
It also doesn't work if I remove the [API KEY] from the url and add it to the data dictionary as "api_key":"[API KEY]"
BTW I'm not passing the key in as a list or anything, I just didn't want to post the physical key in my question.
I'm a total newb to python and stackoverflow, but I've done my due diligence and have been searching out answers and testing different ways to format the request for a few hours now. Any help is greatly appreciated!
It's probably because requests does not parse the API KEY from the URL, try this:
response = requests.post('http://api.nal.usda.gov/ndb/V2/reports', headers=headers, data=data, auth=(API_KEY, ''))
This passes it using Basic Authentication (Authorization header) which is the same behavior that curl does when parsing the URL.
Normally in Basic Auth you would have the username and the password. E.g:
auth=('<username>', '<password>')
Since this API only seems to care about the username, I have left the password as blank.