Retrieve files from only the third level of directory

Question

I have a directory which has the following form :

A/ : the root

B/: The first level subdirectory which contains the following directories

01/  02/ 03/ 04/ 05/ 06/ 07/

C/: third leve where each subdirectory from B/ (01/ or 02/ or 03/ or 04/ or 05/ or 06/ or 07/) contains up to three subdirectories

001/ 002/ 003/

It's at 001/ 002/ 003/ that l want to retrieve files :

My tree is as follow : A/B/C/01/001/files.txt

How can l access that ?

What l have tried ?

    for root, dirs,files in sorted(os.walk(path+ "/", topdown=False)):  # root

        for lab in dirs:  # level 1 
            new_path=path+category+'/'+lab+'/'
            for ro,dir,f in os.walk(new_path): #level 2
                for dr in dir:
                    for ri, dir, file in os.walk(new_path+'/'+dr): #level 3 
                        os.chdir(new_path+'/'+dr)
                        text_file=glob.glob("*.txt")

Is there any efficient way to do that avoiding 5 nested for loops ?

Answer 1

This alone when I try works for me

import os

path = r'C:\root'

for root, dirs,files in os.walk(path):  # root
    for f in files:
        print(f)

This outputs all files on level 3. Which is essentially files contained in the three subdirectories 001/ 002/ 003/ from each of the 7 directories on level B.