How do I make my array print repetitions of an input once? (JAVA)

Question

I have to design a program that takes in arbitrary input from 0-50, prints out all the inputs ONCE, and then prints out the occurrence of each input.

I have it working to some degree, but, when the input is: 1 , 2 , 3 , 3 , 3 , 6 , 9 , 0 , 0

It prints out:

Input : Occurrence

     Number   Times
      1         1
      2         1
      3         1
      3         2
      3         3
      6         1
      9         1
      0         1
      0         1

instead of:

Input : Occurrence

     Number Times
       0    2
       1    1
       2    1
       3    3
       6    1
       9    1

This is a beginner course and most of the solutions I've seen online seem to be advanced using some kind of mapping technique that I haven't learned yet.

 public static void main(String [] args)
{

   int[] array = new int[51];
   Scanner scan = new Scanner(System.in);
   System.out.println("Number \t   Times");

   while (scan.hasNext()){    
    int x = scan.nextInt();
    if (x>=0 && x<=50){
        array[x]++;
  System.out.println(x + "\t      " + array[x]);
      }
    }
  }
}

I've tried multiple ways of formatting the loops but I can't seem to find out how to get it to print a number that is input multiple times just once.

Answer 1

Here's another answer if you're still looking. I'll leave the hashmaps answer as other people might find that useful, but I decided to also get your current code working.

int[] numbers = new int[51];

// Small loop to get the number input
Scanner scanner = new Scanner(System.in);
for (int i=0; i<10; i++) {
    System.out.print("> ");
    int x = scanner.nextInt();

    if (x >= 0 && x <= 50) {
        numbers[x] += 1;
    }
}

// Now display the results after getting input
System.out.println("Number \t     Times");
for (int i=0; i<numbers.length; i++) {
    if (numbers[i] != 0) {
        System.out.println(i + "\t\t" + numbers[i]);
    }
}