The method/function needs to return an array that has elements in the 1st array that are not present in the second array.
like,
var arr1 = [1,2,3];
var arr2 = [2,3,4,5,6];
should return [1]; and I need to do this using .filter() method!
You can use Array.filter()
with Array.includes()
:
const arr1 = [1,2,3];
const arr2 = [2,3,4,5,6];
const difference = (a, b) => a.filter(item => !b.includes(item));
const result = difference(arr1, arr2);
console.log(result);