I wish to get analytical (closed form) solution to the following integral in Matlab. However, Matlab gives me an answer with real & imaginary parts. How do I get it to produce an answer with just the "real" part. Here is the full code.
close all;
clear all;
clc;
syms t real;
syms thetak real;
syms sik real;
syms tbar real;
syms sjk real;
expr = exp(-thetak*((t-sik)^2 + (t-sjk)^2));
Bijk_raw = int(expr,t,0,1);
Bijk = simplify(collect(expand(Bijk_raw)));
fprintf('Bijk is as follows...\n');
pretty(Bijk);
The answer you obtain (if you have a Matlab version similar to mine) and that I reproduce here :
/ / 2 \
| 1/2 1/2 | thetak (sik - sjk) |
- | 2 pi exp| - ------------------- |
\ \ 2 /
/ / 1/2 1/2 \
| | 2 (-thetak) (sik i + sjk i) |
| erf| --------------------------------- | i -
\ \ 2 /
/ 1/2 1/2 \ \ \
| 2 (-thetak) (sik i + sjk i - 2 i) | | |
erf| --------------------------------------- | i | | /
\ 2 / / /
1/2
(4 (-thetak) )
gives the impression that you have complex number i everywhere.
But in fact it is a false impression due to (-thetak)^(1/2).
Indeed, taking the square root of a negative number will generate a "i" which in turn will "kill" the other "i"s that are "in contact" with it. This cancellation will occur at different places due to the fact that (-thetak)^(1/2) can be found :
1) inside the erf expressions and
2) as a common denominator (last line).
Verify that rule i^2=-1 applies everywhere leaving no chance to the survival of any "i"...
Finally giving (I have set thetak=s^2 with s>0) :
/ / \
| 1/2 1/2 | s^2 (sik - sjk)^2 |
- | 2 pi exp| - ------------------- |
\ \ 2 /
/ / 1/2 \
| | 2 s (sik + sjk ) |
| erf| ----------------------- | -
\ \ 2 /
/ 1/2 \ \ \
| 2 s (sik + sjk - 2 ) | | |
erf| ----------------------------- | | | / (4 s)
\ 2 / / /
Edit : You could have escaped integration. The idea is to convert the quadratic in $exp(-thetak*((t-sik)^2 + (t-sjk)^2))$ under the so-called "canonical form" which in your case is: $exp(-thetak*(((t-A)^2 + B))/C);$ where $A,B,C$ can be expressed as fonctions of sik and sjk (for example $A=(sik+sjk)/2$); in this way, setting $T=t-A$, you are brought back to a classical Gauss integral with formula :
$$\frac{2}/{\sqrt{\pi}} \int_a^b exp(-t^2} dt ) (erf(b) - erf(a))$$