Is there a way to find the solution of problem like this;
if my age on 10/jan/2010 was 2 year how much will be the age on 10/April/2012.
kind regards
Simply use difftime()
to calculate the difference and then add the age. Something like this:
earlier_age <- 2
diff <- as.numeric(difftime(latest_date, earlier_date), units="years")
#make sure that dates are actually date objects (using as.Date())
new_age <- diff + earlier_age
#So for your example:
latest_date <- as.Date("10/April/2012", format = "%d/%B/%Y")
earlier_date <- as.Date("10/jan/2010", format = "%d/%b/%Y")
earlier_age <- 2
diff <- as.numeric(difftime(latest_date, earlier_date), units="days")/365.25
new_age <- diff + earlier_age
You can change the units to weeks, hours and so on as per your requirement