I have a Django blog application wherein while posting a blog, a file can be attached and submit as well.
Here is the views.py code:
def user_own_blog(request):
if request.method == 'POST' and request.FILES['blog_document']:
title_b = request.POST.get('blog_title')
content_b = request.POST.get('blog_content')
file1 = request.FILES['blog_document']
fs = FileSystemStorage()
document_name = fs.save(file1.name, file1)
uploaded_document_url = fs.url(document_name)
b = Blog(title=title_b, content=content_b, blog_document=uploaded_document_url)
b.save()
return render(request, 'mysite/portfolio.html')
else:
return render(request, 'mysite/blog.html')
And here is the MEDIA_ROOT and MEDIA_URL path names:
STATIC_URL = '/static/'
MEDIA_URL = '/media/'
MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
And following is the code for urls.py inside mysite app:
urlpatterns=[ .....
......
] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
This is the project structure, wherein I need the media folder to be present directly under the Assignment1 project
While the file is getting uploaded successfully, it shows up as follows in the /api.
But there are two media paths being created: /media/media as shown below: I am not able to find the duplicate fields that I might have created.
And on clicking the file link: the 404 not found error occurs. I think the MEDIA_ROOT file name is not correct.
HTML code for blog.html:
{% extends 'mysite/base.html' %}
{% load static %}
{% block content %}
<div class="container">
<div class="row">
<div class="col-sm-6 mx-auto" style="margin-top: 70px">
<form action="{% url 'user_own_blog' %}" method="POST" enctype="multipart/form-data">
{% csrf_token %}
<div class="form-group row">
<label for="example-email-input" class="col-2 col-form-label">Title</label>
<div class="col-10">
<input name = "blog_title" class="form-control" type="text">
</div>
</div>
<div class="form-group row">
<label for="example-email-input" class="col-2 col-form-label">Content</label>
<div class="col-10">
<textarea name = "blog_content" class="form-control" rows = "5" cols = "50" type="text"> </textarea>
</div>
</div>
<div class="form-group row">
<label for="example-email-input" class="col-2 col-form-label">Upload File</label>
<div class="col-10">
<input name = "blog_document" class="form-control" type="file">
</div>
</div>
<div class="pull-right">
<button type="submit" class="btn btn-primary float-right">Post</button>
</div>
</form>
</div>
</div>
</div>
{% endblock %}
If you want to locate the uploaded file location in the root:
MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
MEDIA_URL = '/media/'
else:
MEDIA_URL = '/media/'
MEDIA_ROOT = 'C:/Users/xyz/Assignment1/mysite/media/' #if windows pay attention to the slashes
Also follow this pattern for your url:
if settings.DEBUG:
urlpatterns += static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
EDIT: I think that the issue is not with the media folder it is how you save and retrieve the document. Below I will put the required parts for proper upload and retrieve.
models.py
blog_document= models.FileField()
views.py
def user_own_blog(request):
if request.method == 'POST' and request.FILES:
form = BlogForm(request.POST,
request.FILES)
blog = Blog()
if form.is_valid():
blog.title_b = form.cleaned_Data['title']
blog.content_b = form.cleaned_Data['content']
blog.file = form.cleaned_Data['blog_document']
blog.save()
return HttpRequestRedirect(reverse('portfolio'))
else:
form = BlogForm()
return render(request,
'mysite/blog.html',
{'form': form})
To retrieve the upload file url there is default method .url
. You just pass the query to the template (Modelname.objects.filter(title__iexact='something')
)
{{ query.file.url}}
Note: You need to create a form in forms.py(if you don't have to create one). And values are retrieved from the form with the cleaned_data method. Research on this.